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Chemistry
The types of hybridisation on the five carbon atoms from left to right in the molecule CH3-CH=C=CH-CH3 are
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Q. The types of hybridisation on the five carbon atoms from left to right in the molecule CH$_3-CH=C=CH-CH_3$ are
KEAM
KEAM 2009
Chemical Bonding and Molecular Structure
A
$sp^3,sp^2,sp^2,sp^2,sp^3$
16%
B
$sp^3,sp,sp^2,sp^2,sp^3$
15%
C
$sp^3,sp^2,sp,sp^2,sp^3$
47%
D
$sp^3,sp^2,sp^2,sp,sp^3$
14%
E
$sp^3,sp,sp,sp^2,sp^3$
14%
Solution:
Number of hybrid orbitals= number of $\sigma$-bonds formed.
