The two diagrams show the situation before and after a collision between two spheres A and B of equal radii moving along the same straight line on a smooth horizontal surface. The coefficient of restitution e is

Question

The two diagrams show the situation before and after a collision between two spheres A and B of equal radii moving along the same straight line on a smooth horizontal surface. The coefficient of restitution e is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-akama4iuksfx.png" /> (A) (2/3) (B) (1/2) (C) (1/3) (D) (1/4)

Tardigrade Admin · Accepted Answer

e=(vs e p/va p p)=(v2 - v1/u1 - u2) u1=8 m s- 1,v1=2 m s- 1 u2=2 m s- 1,v2=5 m s- 1

Q. The two diagrams show the situation before and after a collision between two spheres $A$ and $B$ of equal radii moving along the same straight line on a smooth horizontal surface. The coefficient of restitution $e$ is

$\frac{2}{3}$

$\frac{1}{2}$

$\frac{1}{3}$

$\frac{1}{4}$

$e = \frac{v _{se p}}{v _{a pp}} = \frac{v _{2} - v _{1}}{u _{1} - u _{2}}$
$u_{1} = 8 m s^{- 1}, v_{1} = 2 m s^{- 1}$
$u_{2} = 2 m s^{- 1}, v_{2} = 5 m s^{- 1}$

Q. The two diagrams show the situation before and after a collision between two spheres A and B of equal radii moving along the same straight line on a smooth horizontal surface. The coefficient of restitution e is

32​

21​

31​

41​