The two bodies of mass 1 kg and 2 kg are attached to the ends of a 2 metre long weight less rod. This system is rotating about an axis passing through middle point of rod. Calculate MI of system

Question

The two bodies of mass 1 kg and 2 kg are attached to the ends of a 2 metre long weight less rod. This system is rotating about an axis passing through middle point of rod. Calculate MI of system (A) 2 kgm 2 (B) 3 kgm 2 (C) 4 kgm 2 (D) 0.5 kgm 2

Tardigrade Admin · Accepted Answer

I=I1+I2 =1 × 12+2 × 12=3 kg M2

Q. The two bodies of mass $1 k g$ and $2 k g$ are attached to the ends of a $2$ metre long weight less rod. This system is rotating about an axis passing through middle point of rod. Calculate MI of system

$2 k g m^{2}$

$3 k g m^{2}$

$4 k g m^{2}$

$0.5 k g m^{2}$

$I = I_{1} + I_{2}$
$= 1 \times 1^{2} + 2 \times 1^{2} = 3 k g M^{2}$

Q. The two bodies of mass 1kg and 2kg are attached to the ends of a 2 metre long weight less rod. This system is rotating about an axis passing through middle point of rod. Calculate MI of system

2kgm2

3kgm2

4kgm2

0.5kgm2