The truth table for the given logic circuit is :

Question

The truth table for the given logic circuit is : (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

C= overlineA ⋅ B ⋅ overline barA ⋅ B using De-Morgan Theorem C= overline A ⋅ B + overline A ⋅ B C = overline B ( A + overline A )= overline B Therefore

Q. The truth table for the given logic circuit is :

$C = \overline{A \cdot B} \cdot \overline{\overset{ˉ}{A}} \cdot B$
using De-Morgan Theorem
$C = \overline{A \cdot B + \overline{A} \cdot B}$
$C = \overline{B (A + \overline{A})} = \overline{B}$
Therefore

Q. The truth table for the given logic circuit is :

C=A⋅B⋅Aˉ⋅B using De-Morgan Theorem C=A⋅B+A⋅B​ C=B(A+A)​=B Therefore

$C = \overline{A \cdot B} \cdot \overline{\overset{ˉ}{A}} \cdot B$
using De-Morgan Theorem
$C = \overline{A \cdot B + \overline{A} \cdot B}$
$C = \overline{B (A + \overline{A})} = \overline{B}$
Therefore