The triad of nuclei that is isotonic is

Question

The triad of nuclei that is isotonic is (A)  1 H 1 and 1 H 2 and 1 H 3 (B)  92235 U , 92237 U and 92238 U (C)  1840 Ar , 1940 K and 2040 Ca (D)  614 C , 715 N and 816 O

Tardigrade Admin · Accepted Answer

Since isotones have the same number of neutrons. 614C ,N=14-6 N=8 715C ,N=15-7 =8 816O ,N=16-8 =8 For all N = 8

Q. The triad of nuclei that is isotonic is

$_{1} H^{1}$ and $_{1} H^{2}$ and $_{1} H^{3}$

$_{92}^{235} U,_{92}^{237} U$ and $_{92}^{238} U$

$_{18}^{40} A r,_{19}^{40} K$ and $_{20}^{40} C a$

$_{6}^{14} C,_{7}^{15} N$ and $_{8}^{16} O$

Since isotones have the same number of neutrons.
$_{6}^{14} C$ $, N = 14 - 6$
$N = 8$
$_{7}^{15} C$ $, N = 15 - 7$
$= 8$
$_{8}^{16} O$ $, N = 16 - 8$
$= 8$
For all N = 8

Q. The triad of nuclei that is isotonic is

1​H1 and 1​H2 and 1​H3

92235​U,92237​U and 92238​U

1840​Ar,1940​K and 2040​Ca

614​C,715​N and 816​O

Since isotones have the same number of neutrons. 614​C ,N=14−6 N=8 715​C ,N=15−7 =8 816​O ,N=16−8 =8 For all N = 8

$_{1} H^{1}$ and $_{1} H^{2}$ and $_{1} H^{3}$

$_{92}^{235} U,_{92}^{237} U$ and $_{92}^{238} U$

$_{18}^{40} A r,_{19}^{40} K$ and $_{20}^{40} C a$

$_{6}^{14} C,_{7}^{15} N$ and $_{8}^{16} O$

Since isotones have the same number of neutrons.
$_{6}^{14} C$ $, N = 14 - 6$
$N = 8$
$_{7}^{15} C$ $, N = 15 - 7$
$= 8$
$_{8}^{16} O$ $, N = 16 - 8$
$= 8$
For all N = 8