Question

The total spin resulting from a $d^7$ configuration is

• A. $\pm 1/2$
• B. $\pm 2$
• C. $\pm 1$
• D. $\pm 3/2$

Answer 1

Answer: (D)

$d^7$ configuration has three unpaired electrons. Thus, total spin = ±1/2 × no. of unpaired electrons
$=\pm \frac{1}{2}\times 3=\pm \frac{3}{2}$