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Question
Mathematics
The total number of terms in the expansion of (x+y)100+(x-y)100 alter simplification is
Q. The total number of terms in the expansion of
(
x
+
y
)
100
+
(
x
−
y
)
100
alter simplification is
3881
230
KCET
KCET 2009
Binomial Theorem
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A
50
19%
B
51
50%
C
202
16%
D
100
15%
Solution:
Let
f
(
x
)
=
(
x
+
y
)
100
+
(
x
−
y
)
100
Here,
n
=
100
, which is even.
∴
Total number of terms
=
2
n
+
2
=
2
100
+
2
=
51