The total number of protons in 10g of calcium carbonate is (N0=6.023× 1023):

Question

The total number of protons in 10g of calcium carbonate is (N0=6.023× 1023):  (A)  3.01× 1024  (B)  ~4.06× 1024  (C)  2.01× 1024  (D)  3.02× 1024

Tardigrade Admin · Accepted Answer

We know that protons in 1 mole CaCO3 = atomic number of calcium + atomic number of carbon + 3 (atomic number of oxygen) =20+6+3(8)=50 mol ∴ proton in 10 g CaCO3=(10× 50/100)× 6.02× 1023 =3.01× 1024

Q. The total number of protons in $10 g$ of calcium carbonate is $(N_{0} = 6.023 \times 10^{23}) :$

$3.01 \times 10^{24}$

$4.06 \times 10^{24}$

$2.01 \times 10^{24}$

$3.02 \times 10^{24}$

We know that protons in 1 mole $C a C O_{3}$ = atomic number of calcium + atomic number of carbon + 3 (atomic number of oxygen) $= 20 + 6 + 3 (8) = 50 m o l$ $∴$ proton in 10 g $C a C O_{3} = \frac{10 \times 50}{100} \times 6.02 \times 10^{23}$ $= 3.01 \times 10^{24}$

Q. The total number of protons in 10g of calcium carbonate is (N0​=6.023×1023):

3.01×1024

4.06×1024

2.01×1024

3.02×1024