Question

The total number of protons in $ 10g $ of calcium carbonate is $ ({{N}_{0}}=6.023\times {{10}^{23}}): $

• A. $ 3.01\times {{10}^{24}} $
• B. $ ~4.06\times {{10}^{24}} $
• C. $ 2.01\times {{10}^{24}} $
• D. $ 3.02\times {{10}^{24}} $

Answer 1

Answer: (A)

We know that protons in 1 mole $ CaC{{O}_{3}} $ = atomic number of calcium + atomic number of carbon + 3 (atomic number of oxygen) $ =20+6+3(8)=50\,mol $ $ \therefore $ proton in 10 g $ CaC{{O}_{3}}=\frac{10\times 50}{100}\times 6.02\times {{10}^{23}} $ $ =3.01\times {{10}^{24}} $