The total number of isomers for C4H8 is

Question

The total number of isomers for C4H8 is (A) 5 (B) 6 (C) 7 (D) 8

Tardigrade Admin · Accepted Answer

The possible isomers of C4H8 are as (i) underset1-butene mathopCH3CH2CH=CH2 (ii) undersettrans 2-butene mathopCH3 oversetH mathop overset| mathopC = undersetH mathop underset| mathopC -CH3 (iii) undersetcis 2-butene mathopCH3CH=CHCH3 (iv) underset2-methyl propane mathopCH3 oversetCH3 mathop overset| mathopC =CH2 (v) and (vi)

Q. The total number of isomers for $C_{4} H_{8}$ is

5

6

7

8

The possible isomers of $C_{4} H_{8}$ are as (i) $1 - b u t e n e C H_{3} C H_{2} C H = C H_{2}$ (ii) $t r an s 2 - b u t e n e C H_{3} C ∣ H = H ∣ C - C H_{3}$ (iii) $c i s 2 - b u t e n e C H_{3} C H = C H C H_{3}$ (iv) $2 - m e t h y l p ro p an e C H_{3} C ∣ C H_{3} = C H_{2}$ (v)
and (vi)

Q. The total number of isomers for C4​H8​ is

5

6

7

8

The possible isomers of C4​H8​ are as (i) 1−buteneCH3​CH2​CH=CH2​​ (ii) trans2−buteneCH3​C∣H=H∣C​​−CH3​​ (iii) cis2−buteneCH3​CH=CHCH3​​ (iv) 2−methylpropaneCH3​C∣CH3​=CH2​​ (v) and (vi)

Q. The total number of isomers for $C_{4} H_{8}$ is