The total number of geometrical isomers possible for an octahedral complex of the type [MA2B2C2] is (M = transition metal; A, B and C are monodentate ligands)

Question

The total number of geometrical isomers possible for an octahedral complex of the type [MA2B2C2] is (M = transition metal; A, B and C are monodentate ligands) (A) 3 (B) 4 (C) 5 (D) 6

Tardigrade Admin · Accepted Answer

Geometrical isomers arises in heteroleptic complexes due to different possible geometric arrangements of ligand. There are 5 geometrical isomers possible for an octahedral complex of the type

[M A_{2} B_{2} C_{2}]

, which are as follows:

Q. The total number of geometrical isomers possible for an octahedral complex of the type [MA2​B2​C2​] is (M= transition metal; A,B and C are monodentate ligands)

3

4

5

6

Geometrical isomers arises in heteroleptic complexes due to different possible geometric arrangements of ligand. There are 5 geometrical isomers possible for an octahedral complex of the type [MA2​B2​C2​] , which are as follows:

Q. The total number of geometrical isomers possible for an octahedral complex of the type $[M A_{2} B_{2} C_{2}]$ is ( $M =$ transition metal; $A, B$ and $C$ are monodentate ligands)

Geometrical isomers arises in heteroleptic complexes due to different possible geometric arrangements of ligand. There are 5 geometrical isomers possible for an octahedral complex of the type $[M A_{2} B_{2} C_{2}]$ , which are as follows: