The total internal energy of two mole monoatomic ideal gas at temperature T =300 K will be J. (Given R =8.31 J / mol . K )

Question

The total internal energy of two mole monoatomic ideal gas at temperature T =300 K will be J. (Given R =8.31 J / mol . K ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

U = nC v T =2 × (3/2) R × 300 =900 R =900 × 8.31=7479 J

Q. The total internal energy of two mole monoatomic ideal gas at temperature $T = 300 K$ will be $J$ .
(Given $R = 8.31 J / m o l . K$ )