The total flux through the faces of the cube with side of length a, if a charge q is placed at B (mid-point of an edge of the cube), is φ1 and if a charge q is placed at C (centre of a face of the cube), is φ2 . Find (φ2/φ1).

Question

The total flux through the faces of the cube with side of length a, if a charge q is placed at B (mid-point of an edge of the cube), is φ1 and if a charge q is placed at C (centre of a face of the cube), is φ2 . Find (φ2/φ1). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(φ2/φ1)=(q/2 ε0) / (q/4 ε0)=2

Q. The total flux through the faces of the cube with side of length $a$ , if a charge $q$ is placed at $B$ (mid-point of an edge of the cube), is $ϕ_{1}$ and if a charge $q$ is placed at $C$ (centre of a face of the cube), is $ϕ_{2} .$ Find $\frac{ϕ _{2}}{ϕ _{1}}$ .

$\frac{ϕ _{2}}{ϕ _{1}} = \frac{q}{2 ε _{0}} / \frac{q}{4 ε _{0}} = 2$

Q. The total flux through the faces of the cube with side of length a, if a charge q is placed at B (mid-point of an edge of the cube), is ϕ1​ and if a charge q is placed at C (centre of a face of the cube), is ϕ2​. Find ϕ1​ϕ2​​.

ϕ1​ϕ2​​=2ε0​q​/4ε0​q​=2

Q. The total flux through the faces of the cube with side of length $a$ , if a charge $q$ is placed at $B$ (mid-point of an edge of the cube), is $ϕ_{1}$ and if a charge $q$ is placed at $C$ (centre of a face of the cube), is $ϕ_{2} .$ Find $\frac{ϕ _{2}}{ϕ _{1}}$ .

$\frac{ϕ _{2}}{ϕ _{1}} = \frac{q}{2 ε _{0}} / \frac{q}{4 ε _{0}} = 2$