The total energy stored in the condenser system shown in the figure will be

Question

The total energy stored in the condenser system shown in the figure will be (A) 2 μ J (B) 4 μ J (C) 8 μ J (D) 16 μ J

Tardigrade Admin · Accepted Answer

6 μ F and 3 μ F capacitors are in series ∴ (1/C1)=(1/6)+(1/3) C1=2 C1 is parallel to 2 μ F capacitor ∴ C eq =2+2=4 μ F Total energy, U=(1/2) C V2=(1/2) × 4 ×(2)2=8 μ

Q. The total energy stored in the condenser system shown in the figure will be

$2 μ J$

$4 μ J$

$8 μ J$

$16 μ J$

$6 μ F$ and $3 μ F$ capacitors are in series
$∴ \frac{1}{C _{1}} = \frac{1}{6} + \frac{1}{3}$
$C_{1} = 2$
$C_{1}$ is parallel to $2 μ F$ capacitor
$∴ C_{e q} = 2 + 2 = 4 μ F$
Total energy, $U = \frac{1}{2} C V^{2} = \frac{1}{2} \times 4 \times (2)^{2} = 8 μ$