Question

The total energy of a simple harmonic oscillator is proportional to

• A. amplitude
• B. square of amplitude
• C. frequency
• D. velocity

Answer 1

Answer: (B)

In $SHM$, the total energy is
$E=\frac{1}{2}m{\omega }^2{A}^2$
where the symbols have their usual meanings.
$E\propto A^2$