Question

The total count of geometrical isomers for a square planar complex $[Mabcd{]}^{n\pm }$ is ${}^{\prime }{x}^{\prime }$ . The number of geometrical isomers possible for octahedral complex of the type ${\left[M{a}_4{b}_2\right]}^{n\pm }$ is ${}^{{}^{\prime }}{y}^{{}^{\prime }}$ . Calculate $x+y$ : _______ ( $a,b,c,d$ are monodentate ligands).

Answer 1

Answer: 5

Total count of geometrical isomers of square planar complex $\left[Mabcd\right]$ is $3$ and $[M{a}_4{b}_2]$ is $2$ .
$Total=5$