Question

The time period of a simple pendulum, when it is made to oscillate on the surface of moon

• A. increases
• B. decreases
• C. remains unchanged
• D. becomes infinite

Answer 1

Answer: (A)

Time period of a simple pendulum of length $l$ is given by
$T=2n\sqrt{\frac{l}{g}}$
where $g$ is acceleration due to gravity.
On moon $g_m=\frac{g}{6}$
$\therefore T^{\prime }=2\pi \sqrt{\frac{l}{g/6}}=2\pi \sqrt{\frac{6l}{g}}$
$=\sqrt{6}.2\pi \sqrt{\frac{l}{g}}$
$\Rightarrow T^{\prime }=\sqrt{6}T$
Hence, time period increases on the surface of moon.