The three resistances of equal value are arranged in the different combinations shown below. Arrange them in increasing order of power dissipation

Question

The three resistances of equal value are arranged in the different combinations shown below. Arrange them in increasing order of power dissipation (A) III < II < IV < I (B) II < III < IV < I (C) I < IV < III < II (D) I < III < II < IV

Tardigrade Admin · Accepted Answer

Let each resistance =R For I: P1=i2 Re q=i2(R+R+R)=i2(3 R) For II: P2=i2 Re q=i2 × (R(R+R)/R+(R+R))=i2(2 R / 3) For III: P3=i2 Re q=i2(R / 3) For IV: P4=i2 Re q=i2 ×(R / 2+R)=i2(3 R / 2) Thus, P 3< P 2< P 4< P 1

Q. The three resistances of equal value are arranged in the different combinations shown below. Arrange them in increasing order of power dissipation

III < II < IV < I

II < III < IV < I

I < IV < III < II

I < III < II < IV

Let each resistance =R For I: P1​=i2Req​=i2(R+R+R)=i2(3R) For II: P2​=i2Req​=i2×R+(R+R)R(R+R)​=i2(2R/3) For III: P3​=i2Req​=i2(R/3) For IV: P4​=i2Req​=i2×(R/2+R)=i2(3R/2) Thus, P3​<P2​<P4​<P1​