Question

The third term of a G.P. is 9. The product of its first five terms is

• A. $3^{10}$
• B. $3^5$
• C. $3^{12}$
• D. $3^9$

Answer 1

Answer: (A)

$Let\frac{a}{r^2}.\frac{a}{r}.a.ar.a{r}^2$ are in G.P., Given a = 9
$\therefore product=9^5=3^{10}$