The thermodynamic equilibrium constant, Kc , for the reaction CuO(s) +H2(g) arrow Cu(s) +H2O(g) is given by

Question

The thermodynamic equilibrium constant, Kc , for the reaction CuO(s) +H2(g) arrow Cu(s) +H2O(g) is given by (A)  Kc=([Cu][H2O]/[CuO][H2])  (B)  Kc=([Cu][H2O]/[H2])  (C)  Kc=([H2O]/[CuO][H2])  (D)  Kc=([H2O]/[H2])

Tardigrade Admin · Accepted Answer

CuO(s) + H2(g) leftharpoons Cu(s) + H2O(g) Kc = ([H2O]/[H2]) (As a general rule, the concentration of pure solids and pure liquids are not included when writing an equilibrium equation.)

Q. The thermodynamic equilibrium constant, $K_{c}$ , for the reaction
$C u O (s) + H_{2} (g) \to C u (s) + H_{2} O (g)$ is given by

$K_{c} = \frac{[ C u ] [ H _{2} O ]}{[ C u O ] [ H _{2} ]}$

$K_{c} = \frac{[ C u ] [ H _{2} O ]}{[ H _{2} ]}$

$K_{c} = \frac{[ H _{2} O ]}{[ C u O ] [ H _{2} ]}$

$K_{c} = \frac{[ H _{2} O ]}{[ H _{2} ]}$

$C u O (s) + H_{2} (g) ⇌ C u (s) + H_{2} O (g)$
$K_{c} = \frac{[ H _{2} O ]}{[ H _{2} ]}$
(As a general rule, the concentration of pure solids and pure liquids are not included when writing an equilibrium equation.)

Q. The thermodynamic equilibrium constant, Kc​ , for the reaction CuO(s)+H2​(g)→Cu(s)+H2​O(g) is given by

Kc​=[CuO][H2​][Cu][H2​O]​

Kc​=[H2​][Cu][H2​O]​

Kc​=[CuO][H2​][H2​O]​

Kc​=[H2​][H2​O]​