The temperatures of two bodies A and B are respectively 727° C and 327° C. The ratio HA: HB of the rates of heat radiated by them is

Question

The temperatures of two bodies A and B are respectively 727° C and 327° C. The ratio HA: HB of the rates of heat radiated by them is (A) 727: 327 (B) 5: 3 (C) 25: 9 (D) 625: 81

Tardigrade Admin · Accepted Answer

As we know Q propto T4 ⇒ (HA/HB)=[(273+727/273+327)]4=(625/81)

Q. The temperatures of two bodies $A$ and $B$ are respectively $72 7^{\circ} C$ and $32 7^{\circ} C$ . The ratio $H_{A} : H_{B}$ of the rates of heat radiated by them is

$727 : 327$

$5 : 3$

$25 : 9$

$625 : 81$

As we know $Q \propto T^{4}$
$\Rightarrow \frac{H _{A}}{H _{B}} = [\frac{273 + 727}{273 + 327}]^{4} = \frac{625}{81}$

Q. The temperatures of two bodies A and B are respectively 727∘C and 327∘C. The ratio HA​:HB​ of the rates of heat radiated by them is

727:327

5:3

25:9

625:81