The temperature of perfect black body is 727° C and its area is 0.1 m2 . If Stefans constant is 5.67 text watt/m2sK-4, then heat radiated by it in 1 minute is:

Question

The temperature of perfect black body is 727° C and its area is 0.1 m2 . If Stefans constant is 5.67 text watt/m2sK-4, then heat radiated by it in 1 minute is: (A) 8100 cal (B) 81000 cal (C) 810 cal (D) 81 cal

Tardigrade Admin · Accepted Answer

Q=Aσ tT4 =(0.1× 5.67× 10-8× 60× (1000)4/4.2) textcal =81000 cal

Q. The temperature of perfect black body is $727^{\circ} C$ and its area is $0.1 m^{2}$ . If Stefans constant is $5.67 w a tt / m^{2} s K^{- 4},$ then heat radiated by it in 1 minute is:

8100 cal

81000 cal

810 cal

81 cal

$Q = A σ t T^{4}$ $= \frac{0.1 \times 5.67 \times 10 ^{- 8} \times 60 \times ( 1000 ) ^{4}}{4.2} cal$ $= 81000 c a l$

Q. The temperature of perfect black body is 727∘C and its area is 0.1m2 . If Stefans constant is 5.67watt/m2sK−4, then heat radiated by it in 1 minute is: