The temperature of a body on Kelvin scale is found to be x K. When it is measured by Fahrenheit thermometer, it is found to be x° F, then the value of x is

Question

The temperature of a body on Kelvin scale is found to be x K. When it is measured by Fahrenheit thermometer, it is found to be x° F, then the value of x is (A) 30 (B) 313 (C) 574.25 (D) 301.25

Tardigrade Admin · Accepted Answer

(F-32/9)=(K-273/5) But given, xo F=x K ∴ (x-32/9)=(x-273/5) 5 x-160=9 x-2457 4 x=2297 x =574.25

Q. The temperature of a body on Kelvin scale is found to be $x K$ . When it is measured by Fahrenheit thermometer, it is found to be $x^{\circ} F$ , then the value of $x$ is

30

313

574.25

301.25

$\frac{F - 32}{9} = \frac{K - 273}{5}$
But given, $x^{o} F = x K$
$∴ \frac{x - 32}{9} = \frac{x - 273}{5} 5 x - 160 = 9 x - 2457$
$4 x = 2297 x = 574.25$

Q. The temperature of a body on Kelvin scale is found to be xK. When it is measured by Fahrenheit thermometer, it is found to be x∘F, then the value of x is

30

313

574.25

301.25

9F−32​=5K−273​ But given, xoF=xK ∴9x−32​=5x−273​5x−160=9x−2457 4x=2297x=574.25

Q. The temperature of a body on Kelvin scale is found to be $x K$ . When it is measured by Fahrenheit thermometer, it is found to be $x^{\circ} F$ , then the value of $x$ is

$\frac{F - 32}{9} = \frac{K - 273}{5}$
But given, $x^{o} F = x K$
$∴ \frac{x - 32}{9} = \frac{x - 273}{5} 5 x - 160 = 9 x - 2457$
$4 x = 2297 x = 574.25$