The temperature coefficient of resistance ot a wire is 0.00125 per ° C. At 300 K temperature its resistance is 1Ω. The resistance of the wire will be 2Ω at

Question

The temperature coefficient of resistance ot a wire is 0.00125 per ° C. At 300 K temperature its resistance is 1Ω. The resistance of the wire will be 2Ω at (A) 1154 K (B) 1100 K (C) 1400 K (D) 1127 K

Tardigrade Admin · Accepted Answer

(R1/R2)= (1+α t1/1+α t2) ⇒ (1/2)= ((1+0.00125 × 27)/(1+0.00125 × t)) ⇒ t=854° C ⇒ T=1127K

Q. The temperature coefficient of resistance ot a wire is $0.00125 p er^{\circ} C$ . At 300 K temperature its resistance is $1Ω$ . The resistance of the wire will be $2Ω$ at

1154 K

1100 K

1400 K

1127 K

$\frac{R _{1}}{R _{2}} = \frac{1 + α t _{1}}{1 + α t _{2}}$
$\Rightarrow \frac{1}{2} = \frac{( 1 + 0.00125 \times 27 )}{( 1 + 0.00125 \times t )}$
$\Rightarrow t = 854^{\circ} C$
$\Rightarrow$ T=1127K

Q. The temperature coefficient of resistance ot a wire is 0.00125per∘C. At 300 K temperature its resistance is 1Ω. The resistance of the wire will be 2Ω at