The temperature coefficient of resistance of a wire is 0.00125/K. At 300 K its resistance is 1 Ω .The resistance of the wire will be 2 Ω at

Question

The temperature coefficient of resistance of a wire is 0.00125/K. At 300 K its resistance is 1 Ω .The resistance of the wire will be 2 Ω at (A) 1154 K (B) 1100 K (C) 1400 K (D) 1127 K

Tardigrade Admin · Accepted Answer

Step 1: Applying Relation between Temperature and Resistance

R = R_{0} (1 + α (T_{2} - T_{1}))

Given Initial resistance at

300 K

is

1Ω

.
Let temperature be T when final resistance becomes

2Ω

\Rightarrow 2Ω = 1Ω (1 + 0.00125 (T - 300 K)) \Rightarrow 1 = \frac{5}{4} \times 1 0^{- 3} (T - 300 K) ∴ T = 1100 K

Q. The temperature coefficient of resistance of a wire is 0.00125/K. At 300K its resistance is 1 Ω .The resistance of the wire will be 2 Ω at

1154 K

1100 K

1400 K

1127 K

Step 1: Applying Relation between Temperature and Resistance R=R0​(1+α(T2​−T1​)) Given Initial resistance at 300K is 1Ω. Let temperature be T when final resistance becomes 2Ω ⇒2Ω=1Ω(1+0.00125(T−300K))⇒1=45​×10−3(T−300K)∴T=1100K​

Q. The temperature coefficient of resistance of a wire is $0.00125/ K$ . At $300 K$ its resistance is 1 $Ω$ .The resistance of the wire will be 2 $Ω$ at