The temperature coefficient of resistance of a wire at 0° C is 0.00125° C -1. At 25° C its resistance is one ohm. The resistance of the wire will be 1.2 ohm at

Question

The temperature coefficient of resistance of a wire at 0° C is 0.00125° C -1. At 25° C its resistance is one ohm. The resistance of the wire will be 1.2 ohm at (A) 225 K (B) 190° C (C) 260° C (D) 185 K

Tardigrade Admin · Accepted Answer

1=R0(1+(0.00125)(25)) 1.2=R0(1+(0.00125) θ) (12/10)=(1+0.00125 θ/1.03125) Solving, we get θ=190° C

Q. The temperature coefficient of resistance of a wire at $0^{\circ} C$ is $0.0012 5^{\circ} C^{- 1}$ . At $2 5^{\circ} C$ its resistance is one ohm. The resistance of the wire will be $1.2 o hm$ at

$225 K$

$19 0^{\circ} C$

$26 0^{\circ} C$

$185 K$

$1 = R_{0} (1 + (0.00125) (25))$
$1.2 = R_{0} (1 + (0.00125) θ)$
$\frac{12}{10} = \frac{1 + 0.00125 θ}{1.03125}$
Solving, we get
$θ = 19 0^{\circ} C$

Q. The temperature coefficient of resistance of a wire at 0∘C is 0.00125∘C−1. At 25∘C its resistance is one ohm. The resistance of the wire will be 1.2ohm at

225K

190∘C

260∘C

185K