The temperature coefficient of a cell whose cell reaction is Pb(.s.)+HgCl2(.aq.) arrow PbCl2(.aq.)+Hg(.l.) ((d E/d T))P=1.5× 10- 4VK- 1 at 298 The change in entropy for the given cell reaction will be

Question

The temperature coefficient of a cell whose cell reaction is Pb(.s.)+HgCl2(.aq.) arrow PbCl2(.aq.)+Hg(.l.) ((d E/d T))P=1.5× 10- 4VK- 1 at 298 The change in entropy for the given cell reaction will be (A) 12.6 (B) 28.95 (C) 56.8 (D) 88.86

Tardigrade Admin · Accepted Answer

((d E/d T))P=(Δ S/n F) 1.5× 10- 4=(Δ S/2 × 96500) Δ S=28.95JK- 1mol- 1 .

Q. The temperature coefficient of a cell whose cell reaction is
$P b (s) + H g C l_{2} (a q) \to P b C l_{2} (a q) + H g (l)$
$(\frac{d E}{d T})_{P} = 1.5 \times 1 0^{- 4} V K^{- 1}$ at 298
The change in entropy for the given cell reaction will be

12.6

28.95

56.8

88.86

$(\frac{d E}{d T})_{P} = \frac{Δ S}{n F}$
$1.5 \times 1 0^{- 4} = \frac{Δ S}{2 \times 96500}$
$Δ S = 28.95 J K^{- 1} m o l^{- 1}$ .

Q. The temperature coefficient of a cell whose cell reaction is Pb(s)+HgCl2​(aq)→PbCl2​(aq)+Hg(l) (dTdE​)P​=1.5×10−4VK−1 at 298 The change in entropy for the given cell reaction will be