The system of the wedge and the block connected by a massless spring as shown in the figure is released with the spring in its natural length. Friction is absent. Maximum elongation in the spring will be

Question

The system of the wedge and the block connected by a massless spring as shown in the figure is released with the spring in its natural length. Friction is absent. Maximum elongation in the spring will be (A) (3 Mg /5 k ) (B) (6 Mg /5 k ) (C) (4 Mg /5 k ) (D) (8 Mg /5 k )

Tardigrade Admin · Accepted Answer

Using conservation of mechanical energy M g(xm sin θ)=(1/2) K xm2 xm=(2 M g sin θ/K)

Q. The system of the wedge and the block connected by a massless spring as shown in the figure is released with the spring in its natural length. Friction is absent. Maximum elongation in the spring will be

$\frac{3 M g}{5 k}$

$\frac{6 M g}{5 k}$

$\frac{4 M g}{5 k}$

$\frac{8 M g}{5 k}$

Using conservation of mechanical energy
$M g (x_{m} sin θ) = \frac{1}{2} K x_{m}^{2}$
$x_{m} = \frac{2 M g s i n θ}{K}$

Q. The system of the wedge and the block connected by a massless spring as shown in the figure is released with the spring in its natural length. Friction is absent. Maximum elongation in the spring will be

5k3Mg​

5k6Mg​

5k4Mg​

5k8Mg​

Using conservation of mechanical energy Mg(xm​sinθ)=21​Kxm2​ xm​=K2Mgsinθ​

$\frac{3 M g}{5 k}$

$\frac{6 M g}{5 k}$

$\frac{4 M g}{5 k}$

$\frac{8 M g}{5 k}$

Using conservation of mechanical energy
$M g (x_{m} sin θ) = \frac{1}{2} K x_{m}^{2}$
$x_{m} = \frac{2 M g s i n θ}{K}$