The susceptibility of a paramagnetic material is 99 . The permeability of the material in Wb / A - m is: [Permeability of free space μ0=4 π × 10-7 Wb / A - m ]

Question

The susceptibility of a paramagnetic material is 99 . The permeability of the material in Wb / A - m is: [Permeability of free space μ0=4 π × 10-7 Wb / A - m ] (A) 4 π × 10-7 (B) 4 π × 10-4 (C) 4 π × 10-5 (D) 4 π × 10-6

Tardigrade Admin · Accepted Answer

Susceptibility chi=99 μr=(μ/μ0)=1+ chi μ=μ0(1+ chi) =4 π × 10-7[1+99] =4 π × 10-5

Q. The susceptibility of a paramagnetic material is $99$ . The permeability of the material in $Wb / A - m$ is : [Permeability of free space $μ_{0} = 4 π \times 1 0^{- 7} Wb / A - m$ ]

$4 π \times 1 0^{- 7}$

$4 π \times 1 0^{- 4}$

$4 π \times 1 0^{- 5}$

$4 π \times 1 0^{- 6}$

Susceptibility $χ = 99$
$μ_{r} = \frac{μ}{μ _{0}} = 1 + χ$
$μ = μ_{0} (1 + χ)$
$= 4 π \times 1 0^{- 7} [1 + 99]$
$= 4 π \times 1 0^{- 5}$

Q. The susceptibility of a paramagnetic material is 99 . The permeability of the material in Wb/A−m is : [Permeability of free space μ0​=4π×10−7Wb/A−m ]

4π×10−7

4π×10−4

4π×10−5

4π×10−6