The surface tension of soap solution is 0.03 N/m. The amount of work done in forming a bubble of radius 5 cm is

Question

The surface tension of soap solution is 0.03 N/m. The amount of work done in forming a bubble of radius 5 cm is (A) 3.77 J (B) 1.885 J (C)  0.95× 10-3J  (D)  1.9× 10-3J

Tardigrade Admin · Accepted Answer

Work done W=8 π R2 T =8 × 3.14(5 × 10-2)2 × 0.03 =1.9 × 10-3 J

Q. The surface tension of soap solution is $0.03 N / m$ . The amount of work done in forming a bubble of radius $5 c m$ is

3.77 J

1.885 J

$0.95 \times 10^{- 3} J$

$1.9 \times 10^{- 3} J$

Work done $W = 8 π R^{2} T$
$= 8 \times 3.14 (5 \times 1 0^{- 2})^{2} \times 0.03$
$= 1.9 \times 1 0^{- 3} J$

Q. The surface tension of soap solution is 0.03N/m. The amount of work done in forming a bubble of radius 5cm is

3.77 J

1.885 J

0.95×10−3J

1.9×10−3J

Work done W=8πR2T =8×3.14(5×10−2)2×0.03 =1.9×10−3J

Q. The surface tension of soap solution is $0.03 N / m$ . The amount of work done in forming a bubble of radius $5 c m$ is

$0.95 \times 10^{- 3} J$

$1.9 \times 10^{- 3} J$

Work done $W = 8 π R^{2} T$
$= 8 \times 3.14 (5 \times 1 0^{- 2})^{2} \times 0.03$
$= 1.9 \times 1 0^{- 3} J$