The sum of the slopes of the lines tangent to both circles x2+y2=1 and (x-6)2+y2=4, is.

Question

The sum of the slopes of the lines tangent to both circles x2+y2=1 and (x-6)2+y2=4, is. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Since both the circles are symmetric about the x-axis, sum of slopes of tangent is 0 .

Q. The sum of the slopes of the lines tangent to both circles $x^{2} + y^{2} = 1$ and $(x - 6)^{2} + y^{2} = 4$ , is________.