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  4. The sum of the slopes of the lines tangent to both circles x2+y2=1 and (x-6)2+y2=4, is.

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Q. The sum of the slopes of the lines tangent to both circles $x^{2}+y^{2}=1$ and $(x-6)^{2}+y^{2}=4$, is________.

Conic Sections

Solution:

Since both the circles are symmetric about the $x$-axis, sum of slopes of tangent is $0$ .