Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The sum of the degree and order of the differential equation (1+y12)2 / 3=y2 is
Q. The sum of the degree and order of the differential equation
(
1
+
y
1
2
)
2/3
=
y
2
is
516
137
KCET
KCET 2022
Differential Equations
Report Error
A
4
34%
B
5
33%
C
6
20%
D
7
13%
Solution:
(
1
+
y
1
2
)
=
(
y
2
)
3
2
+
3
=
5