The sum of the coefficients in the expansion of (a2x2 - 6ax + 11)10, where a is constant, is 1024, then the value of a is

Question

The sum of the coefficients in the expansion of (a2x2 - 6ax + 11)10, where a is constant, is 1024, then the value of a is (A) 5 (B) 1 (C) 2 (D) 3

Tardigrade Admin · Accepted Answer

The sum of coefficients in the expansion (a2x2 - 6ax + 11)10 can be obtained by putting x = 1 ⇒ (a2(1)2 - 6a(1) + (11))10 = 1024 ⇒ (a2 - 6a + 11)10 = 210 ⇒ a2 - 6a + 11 = 2 ⇒ a = 3

Q. The sum of the coefficients in the expansion of $(a^{2} x^{2} - 6 a x + 11)^{10}$ , where $a$ is constant, is $1024$ , then the value of $a$ is

$5$

$1$

$2$

$3$

The sum of coefficients in the expansion
$(a^{2} x^{2} - 6 a x + 11)^{10}$ can be obtained by putting $x = 1$
$\Rightarrow (a^{2} (1)^{2} - 6 a (1) + (11))^{10} = 1024$
$\Rightarrow (a^{2} - 6 a + 11)^{10} = 2^{10}$
$\Rightarrow a^{2} - 6 a + 11 = 2$
$\Rightarrow a = 3$

Q. The sum of the coefficients in the expansion of (a2x2−6ax+11)10, where a is constant, is 1024, then the value of a is

5

1

2

3

The sum of coefficients in the expansion (a2x2−6ax+11)10 can be obtained by putting x=1 ⇒(a2(1)2−6a(1)+(11))10=1024 ⇒(a2−6a+11)10=210 ⇒a2−6a+11=2 ⇒a=3

Q. The sum of the coefficients in the expansion of $(a^{2} x^{2} - 6 a x + 11)^{10}$ , where $a$ is constant, is $1024$ , then the value of $a$ is

$5$

$1$

$2$

$3$

The sum of coefficients in the expansion
$(a^{2} x^{2} - 6 a x + 11)^{10}$ can be obtained by putting $x = 1$
$\Rightarrow (a^{2} (1)^{2} - 6 a (1) + (11))^{10} = 1024$
$\Rightarrow (a^{2} - 6 a + 11)^{10} = 2^{10}$
$\Rightarrow a^{2} - 6 a + 11 = 2$
$\Rightarrow a = 3$