The sum of coordination number and oxidation number of the metal M in the complex [M(en)2(C2O4)]Cl (where en is ethylenediamine) is :-

Question

The sum of coordination number and oxidation number of the metal M in the complex [M(en)2(C2O4)]Cl (where en is ethylenediamine) is :- (A) 7 (B) 8 (C) 9 (D) 6

Tardigrade Admin · Accepted Answer

[M(en)2(C2O4)]Cl oxidation state of M = + 3 Coordination number of M = 6 . Sum of oxidation state + coordination number = 3 + 6 = 9

Q. The sum of coordination number and oxidation number of the metal M in the complex $[M (e n)_{2} (C_{2} O_{4})] Cl$ (where en is ethylenediamine) is :-

7

8

9

6

$[M (e n)_{2} (C_{2} O_{4})] Cl$
oxidation state of M = + 3
Coordination number of M = 6
. Sum of oxidation state + coordination number
= 3 + 6 = 9

Q. The sum of coordination number and oxidation number of the metal M in the complex [M(en)2​(C2​O4​)]Cl (where en is ethylenediamine) is :-

7

8

9

6

[M(en)2​(C2​O4​)]Cl oxidation state of M = + 3 Coordination number of M = 6 . Sum of oxidation state + coordination number = 3 + 6 = 9

Q. The sum of coordination number and oxidation number of the metal M in the complex $[M (e n)_{2} (C_{2} O_{4})] Cl$ (where en is ethylenediamine) is :-

$[M (e n)_{2} (C_{2} O_{4})] Cl$
oxidation state of M = + 3
Coordination number of M = 6
. Sum of oxidation state + coordination number
= 3 + 6 = 9