Let ' a ' be the first term and ' r ' be the common ration of the GP.
Then, 1−ra=45 ⇒a=45(1−r)...(i)
Also, a+ar=25 ⇒a(1+r)=25 45(1−r)(1−r)=25{∵ from equation (i)} 1−r2=4525=95 ⇒r2=94⇒r=±32
When r=32 then a=45×32=30
Second term =ar=30×32=20
where r=3−2, the term of the GP will become negative
Hence, the second term is 20 .