Sum of odd numbers between 1 and 1000 , which is
divisible by 3=3+9+15+21+27+.......+999=S (let) ∴ Let n be the number of terms in series and a is first term. ∴l=a+(n−1)d,
where l is last term and d is is common difference. 999=3+(n−1)×6 n−1=6999−3=6996 ⇒n−1=166 ⇒n=167 ∴S=2n[2a+(n−1)d]=2167[2×3+(167−1)×6] =2167[1002]=167×501=83667