Sum of all the interior angles of a polygon of side n=(n−2)⋅180∘ sum of the interior angles if one angle is x∘ (n−2)180∘−x∘=2570∘ x=(n−2)180∘−2570∘ x=180∘n−360∘−2570∘=180∘n−2930∘ ∴0<180∘n−2930∘<180∘ (as x is the interior angle of the polygon) 2930<180n<3110 16.2<n<17.3 ⇒n=17 hence x=15⋅180−2570 =10[270−257]=130∘