Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The sum 10 C 3+ 11 C 3+ 12 C 3+ ldots ldots ldots . .+ 20 C 3 is equal to
Q. The sum
10
C
3
+
11
C
3
+
12
C
3
+
………
..
+
20
C
3
is equal to
289
150
Binomial Theorem
Report Error
A
21
C
4
B
21
C
4
−
10
C
4
C
21
C
4
−
11
C
4
D
21
C
17
Solution:
10
C
3
+
11
C
3
+
12
C
3
+
……
.
+
20
C
3
=
10
C
4
+
10
C
3
+
11
C
3
+
1
2
C
3
+
……
.
+
20
C
3
−
10
C
4
=
11
C
4
+
11
C
3
+
12
C
3
+
……
..
+
20
C
3
−
10
C
4
=
21
C
4
−
10
C
4
=
21
C
17
−
10
C
6
.