Question

The structure of $XeO{F}_4$ is

• A. tetrahedral
• B. square pyramidal
• C. square planar
• D. octahedral

Answer 1

Answer: (B)

In this molecule, $Xe$ has $s{p}^3{d}^2$ hybridisation. One orbital will have a lone pair of electrons and thus the geometry will be square pyramidal.