The strong nuclear force inside a nucleus is given by F=(Ce-kr/r2), where r is position. Dimensions of C and k are, respectively,

Question

The strong nuclear force inside a nucleus is given by F=(Ce-kr/r2), where r is position. Dimensions of C and k are, respectively, (A) [M2L3T-2], [L] (B) [ML3T-2], [L-1] (C) [MLT-2], [L-1] (D) [ML3T-2], [L0]

Tardigrade Admin · Accepted Answer

[C]=[Fr2]=[MLT-2][L2]=[ML3T-2], [k]=[(1/r)]=[L-1]

Q. The strong nuclear force inside a nucleus is given by $F = \frac{C e ^{- k r}}{r ^{2}}$ , where $r$ is position. Dimensions of $C$ and $k$ are, respectively,

$[M^{2} L^{3} T^{- 2}]$ , $[L]$

$[M L^{3} T^{- 2}], [L^{- 1}]$

$[M L T^{- 2}]$ , $[L^{- 1}]$

$[M L^{3} T^{- 2}], [L^{0}]$

$[C] = [F r^{2}] = [M L T^{- 2}] [L^{2}] = [M L^{3} T^{- 2}], [k] = [\frac{1}{r}] = [L^{- 1}]$

Q. The strong nuclear force inside a nucleus is given by F=r2Ce−kr​, where r is position. Dimensions of C and k are, respectively,

[M2L3T−2], [L]

[ML3T−2],[L−1]

[MLT−2], [L−1]

[ML3T−2],[L0]