The string of a violin has a frequency of 440 cps. If the violin string is shortened by one fifth, its frequency will be changed to

Question

The string of a violin has a frequency of 440 cps. If the violin string is shortened by one fifth, its frequency will be changed to (A) 440 cps (B) 880 cps (C) 550 cps (D) 2200 cps

Tardigrade Admin · Accepted Answer

Fundamental frequency =440 cps =(v/2 l) If l is made one fifth (v/2 × l / 5) or (5 v/2 l) Since (v/2 l)=440 5 (v/2 l)=5 × 440=2200

Q. The string of a violin has a frequency of $440 c p s$ . If the violin string is shortened by one fifth, its frequency will be changed to

440 cps

880 cps

550 cps

2200 cps

Fundamental frequency $= 440 c p s = \frac{v}{2 l}$
If $l$ is made one fifth $\frac{v}{2 \times l /5}$ or $\frac{5 v}{2 l}$
Since $\frac{v}{2 l} = 440$
$5 \frac{v}{2 l} = 5 \times 440 = 2200$

Q. The string of a violin has a frequency of 440cps. If the violin string is shortened by one fifth, its frequency will be changed to