Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The strength of 10- 2 M Na2CO3 solution interms of molality will be (density of the solution =1.10 gml- 1 ) (M. wt mathrmNa2 mathrmCO3=106 )
Q. The strength of
1
0
−
2
M
N
a
2
C
O
3
solution interms of molality will be (density of the solution
=
1.10
g
m
l
−
1
)
(M. wt
Na
2
CO
3
=
106
)
2518
201
NTA Abhyas
NTA Abhyas 2020
Some Basic Concepts of Chemistry
Report Error
A
9
×
1
0
−
3
23%
B
1.15
×
1
0
−
2
26%
C
5.1
×
1
0
−
3
31%
D
11.2
×
1
0
−
3
20%
Solution:
m
=
(
1000
×
d
−
17
×
M
.
W
)
17
×
1000
m
=
1000
×
1.1
−
1
0
−
2
×
106
1
0
−
2
×
1000
=
1099.4
10
=
9
×
1
0
−
3