The strength of 10- 2 M Na2CO3 solution interms of molality will be (density of the solution =1.10 gml- 1 ) ( textM . ( textwt Na)2 ( textCO)3 = 106)

Question

The strength of 10- 2 M Na2CO3 solution interms of molality will be (density of the solution =1.10 gml- 1 ) ( textM . ( textwt Na)2 ( textCO)3 = 106) (A) 9× 10- 3 (B) 1.15× 10- 2 (C) 5.1× 10- 3 (D) 11.2× 10- 3

Tardigrade Admin · Accepted Answer

m=(17 × 1000/(. 1000 × d - 17 × M . W .)) m=(1 0- 2 × 1000/1000 × 1.1 - 1 0- 2 × 106)=(10/1099.4)=9× 10- 3

Q. The strength of $1 0^{- 2} M N a_{2} C O_{3}$ solution interms of molality will be (density of the solution $= 1.10 g m l^{- 1}$ )
$(M . (wt Na)_{2} (CO)_{3} = 106)$

$9 \times 1 0^{- 3}$

$1.15 \times 1 0^{- 2}$

$5.1 \times 1 0^{- 3}$

$11.2 \times 1 0^{- 3}$

$m = \frac{17 \times 1000}{( 1000 \times d - 17 \times M . W )}$
$m = \frac{1 0 ^{- 2} \times 1000}{1000 \times 1.1 - 1 0 ^{- 2} \times 106} = \frac{10}{1099.4} = 9 \times 1 0^{- 3}$

Q. The strength of 10−2MNa2​CO3​ solution interms of molality will be (density of the solution =1.10gml−1 ) (M.(wt Na)2​(CO)3​=106)

9×10−3

1.15×10−2

5.1×10−3

11.2×10−3