Q.
The straight lines l1,l2 and l3 are parallel and lie in the same plane. A total numbers of m points are taken on l1;n points on l2,k points on l3. The maximum number of triangles formed with vertices at these points are
Here, the total number of points are (m+n+k) which must give m+n+kC3 combinations by taking 3 points at a time, but m points lying on l1, therefore taking 3 points at a time gives mC3 combinations which produces no triangle. Similarly, nC3 and kC3 number of triangles cannot be formed. Therefore, the required number of triangles is (m+n+k)C3−mC3−nC3−kC3.