Q.
The steady state current through the battery in the circuit given below is
2615
117
J & K CETJ & K CET 2010Current Electricity
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Solution:
In steady state, the branch containing capacitor will become ineffective (ie, we can ignore 1Ω resistance)
The equivalent circuit will now be ∴Req=R1+R2R1×R2 =5+25×2=710
Now, V=iR10=7i×10 ⇒i=7A