The standard reduction potential values of three metallic cations, X, Y, Z are 0.52, - 3.03 and - 1.18 V respectively. The order of reducing power of the corresponding metals is

Question

The standard reduction potential values of three metallic cations, X, Y, Z are 0.52, - 3.03 and - 1.18 V respectively. The order of reducing power of the corresponding metals is (A) Y > Z > X (B) X > Y > Z (C) Z > Y > X (D) Z > X > Y

Tardigrade Admin · Accepted Answer

Lower the value of E°, stronger the reducing agent. Reducing power: Y(E°=-3.03 V ) >Z(E°=-1.18 V ) >X(E°=0.52 V )

Q. The standard reduction potential values of three metallic cations, $X, Y, Z$ are $0.52, - 3.03$ and $- 1.18 V$ respectively. The order of reducing power of the corresponding metals is

Y > Z > X

X > Y > Z

Z > Y > X

Z > X > Y

Lower the value of $E^{\circ}$ , stronger the reducing agent. Reducing power:
$Y (E^{\circ} = - 3.03 V) > Z (E^{\circ} = - 1.18 V) > X (E^{\circ} = 0.52 V)$

Q. The standard reduction potential values of three metallic cations, X,Y,Z are 0.52,−3.03 and −1.18V respectively. The order of reducing power of the corresponding metals is