The standard reduction potential of three metals X,Y and Z are 0.52, -3.03 and -1.18 V respectively. The order or reducing power of the corresponding metals is

Question

The standard reduction potential of three metals X,Y and Z are 0.52, -3.03 and -1.18 V respectively. The order or reducing power of the corresponding metals is (A)  Y>Z>X  (B)  X>Y>Z  (C)  Z>Y>X  (D)  Z>X>Y

Tardigrade Admin · Accepted Answer

More negative is the value of reduction potential, higher is the reducing power. The order of reduction potential is

^{'} Y^{'} - 3.03 V >^{'} Z^{'} - 1.18 V >^{'} X^{'} 0.52

Thus, the order of reducing power is

Y > Z > X

Q. The standard reduction potential of three metals $X, Y$ and $Z$ are $0.52, - 3.03$ and $- 1.18 V$ respectively. The order or reducing power of the corresponding metals is

$Y > Z > X$

$X > Y > Z$

$Z > Y > X$

$Z > X > Y$

More negative is the value of reduction potential, higher is the reducing power. The order of reduction potential is
$^{'} Y^{'} - 3.03 V >^{'} Z^{'} - 1.18 V >^{'} X^{'} 0.52$
Thus, the order of reducing power is
$Y > Z > X$

Q. The standard reduction potential of three metals X,Y and Z are 0.52,−3.03 and −1.18V respectively. The order or reducing power of the corresponding metals is

Y>Z>X

X>Y>Z

Z>Y>X

Z>X>Y