The standard reduction potential for Fe2+ | Fe and Sn2+ | Sn electrodes are - 0.44 and - 0.14 volt respectively. For the cell reaction Fe2+ + Sn → Fe + Sn2+, the standard emf is

Question

The standard reduction potential for Fe2+ | Fe and Sn2+ | Sn electrodes are - 0.44 and - 0.14 volt respectively. For the cell reaction Fe2+ + Sn → Fe + Sn2+, the standard emf is (A) + 0.30 V (B) -0 .58 V (C) + 0.58 V (D) -0 .30 V

Tardigrade Admin · Accepted Answer

2e- + Fe2+ → Fe (Reduction-half reaction) Sn → Sn2+ + 2e- (Oxidation-half reaction) E°cell = - 0.44 + 0.14 = - 0.30 V

Q. The standard reduction potential for $F e^{2 +}$ | $F e$ and $S n^{2 +}$ | $S n$ electrodes are $- 0.44$ and $- 0.14$ volt respectively. For the cell reaction
$F e^{2 +} + S n \to F e + S n^{2 +}$ , the standard emf is

$+ 0.30 V$

$- 0.58 V$

$+ 0.58 V$

$- 0.30 V$

$2 e^{-} + F e^{2 +} \to F e$ (Reduction-half reaction)
$S n \to S n^{2 +} + 2 e^{-}$ (Oxidation-half reaction)
$E_{ce ll}^{\circ} = - 0.44 + 0.14 = - 0.30 V$

Q. The standard reduction potential for Fe2+ | Fe and Sn2+ | Sn electrodes are −0.44 and −0.14 volt respectively. For the cell reaction Fe2++Sn→Fe+Sn2+, the standard emf is

+0.30V

−0.58V

+0.58V

−0.30V