The standard reduction electrode potentials of the three electrodes P, Q and R are respectively -1.76 V,0.34 V and 0.8 V, then

Question

The standard reduction electrode potentials of the three electrodes P, Q and R are respectively -1.76 V,0.34 V and 0.8 V, then (A) metal Q will displace the cation of P from its aqueous solution and deposit the metal P (B) both metals Q and R will displace the cation of P from its aqueous solution and deposit the metal P (C) metal R will displace the cation of P from its aqueous solution and deposit the metal P (D) metal P will displace the cation of R from its aqueous solution and deposit the metal R

Tardigrade Admin · Accepted Answer

The metal that has less standard reduction electrode potential or more negative reduction potential, can displace the other metals (cations) from their aqueous solution. Among the given, P has most negative standard reduction potential, so it will displace Q and R cations from the aqueous solution and deposit them.

Q. The standard reduction electrode potentials of the three electrodes $P, Q$ and $R$ are respectively $- 1.76 V, 0.34 V$ and $0.8 V$ , then

metal $Q$ will displace the cation of $P$ from its aqueous solution and deposit the metal $P$

both metals $Q$ and $R$ will displace the cation of $P$ from its aqueous solution and deposit the metal $P$

metal $R$ will displace the cation of $P$ from its aqueous solution and deposit the metal $P$

metal $P$ will displace the cation of $R$ from its aqueous solution and deposit the metal $R$

Q. The standard reduction electrode potentials of the three electrodes P,Q and R are respectively −1.76V,0.34V and 0.8V, then

metal Q will displace the cation of P from its aqueous solution and deposit the metal P

both metals Q and R will displace the cation of P from its aqueous solution and deposit the metal P

metal R will displace the cation of P from its aqueous solution and deposit the metal P

metal P will displace the cation of R from its aqueous solution and deposit the metal R

Q. The standard reduction electrode potentials of the three electrodes $P, Q$ and $R$ are respectively $- 1.76 V, 0.34 V$ and $0.8 V$ , then

metal $Q$ will displace the cation of $P$ from its aqueous solution and deposit the metal $P$

both metals $Q$ and $R$ will displace the cation of $P$ from its aqueous solution and deposit the metal $P$

metal $R$ will displace the cation of $P$ from its aqueous solution and deposit the metal $P$

metal $P$ will displace the cation of $R$ from its aqueous solution and deposit the metal $R$